1. Consider the quadratic function f(x) –2x2 + = 5x + 2. Find the y-intercept and the equation of the axis of symmetry.
Write the following quadratic function in the vertex form. Then, identify the axis of symmetry.
2. y = x2 + 4x – 6 = 0
3. y = -3x2 – 18x
Find the coordinates of the vertex of the quadratic function.
4. y = -5x2 + 20x – 13
5. Write an equation for the parabola whose vertex is at (2,6) and which passes through (4, -4).
6. Graph the quadratic equation or inequality. y = (x – 2)2 – 5
Answers (highlight below)
1. The y-intercept is + 2. The equation of axis of symmetry is x = (5/4)
2. The vertex form of the function is y = (x+2)2 – 10. The equation of the axis of symmetry is x = -2.
3. The vertex form of the function is y = -3(x – 3)2 + 27. The equation of the axis of symmetry is x = 3.
4. (2,7))
5. y = -2.5(x – 2)2 + 6
6. Goes through points (-1, 4) (0, 1) (4, -1) (5, 4)
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