### Question 1

Suppose that two objects attract each other with a force of 16 units. If the distance between the two objects is doubled, what is the new force of attraction between the two objects?

### Question 2

Suppose that two objects attract each other with a force of 16 units. If the distance between the two objects is reduced in half, then what is the new force of attraction between the two objects?

### Question 3

Suppose that two objects attract each other with a force of 16 units. If the mass of both objects was doubled, and if the distance between the objects remained the same, then what would be the new force of attraction between the two objects?

### Question 4

Suppose that two objects attract each other with a force of 16 units. If the mass of both objects was doubled, and if the distance between the objects was doubled, then what would be the new force of attraction between the two objects?

### Question 5

Suppose that two objects attract each other with a force of 16 units. If the mass of both objects was tripled, and if the distance between the objects was doubled, then what would be the new force of attraction between the two objects?

### Question 6

Suppose that two objects attract each other with a force of 16 units. If the mass of object 1 was doubled, and if the distance between the objects was tripled, then what would be the new force of attraction between the two objects?

### Question 7

If you wanted to make a profit in buying gold by weight at one altitude and selling it at another altitude for the same price per weight, should you buy or sell at the higher altitude location? What kind of scale must you use for this work?

Answer (You should buy at extreme altitude where acceleration due to gravity is less, and sell at sea level where it reaches its maximum, using a scale which measures force of gravity using a spring or electronic sensor, not a balance.)

### Question 8

What would happen to your weight if the mass of the Earth somehow increased by 10%?

### Question 9

Determine the force of gravitational attraction between the earth (m = 5.98 x 10^24kg) and a 70-kg physics student if the student is standing at sea level, a distance of 6.37 x10^6 m from earth’s center.

Answer (F=G ((70kg) 5.98e24 kg /((6.37e6 m)^2))= 688.1N)

### Question 10

Determine the force of gravitational attraction between the earth (m = 5.98 x 10^24 kg) and a 70-kg physics student if the student is in an airplane at 40000 feet above earth’s surface. This would place the student a distance of 6.38 x 10^6 m from earth’s center.

Answer (F=G((70kg) 5.98e24 kg /((6.38e6 m)^2))=685.9N)

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