Lesson 12
- 3, 1, 5, 2, 4
- B
- B
- B, A, A, A, B
- B, A, B, A
- C
- D
- B
- Experiment is to determine whether the hypothesis is correct. If not, alter the hypothesis and conduct additional experiments to test the new hypothesis. (It is
often an ongoing process for scientists.) Or similar answer. - Safe, unsafe, safe, unsafe, unsafe (obstructs sight), safe, unsafe
- B
- C
- B, D, C, A
- 8.0cm³
- 31.0mL
- 24.0g
- 160,000
- 5x 10³
- 5.6 x 10⁻³
- 0.097
- 3.35 x 10⁻¹s
- 4.5 x 10-5 dL
- 3.5 x 10⁻³ km
- 6.7 x 10⁻¹ g
- 3
- 2
- 3 (the final zero is significant)
- 4
- 2
- 3 (the final zero is significant)
Lesson 19
silver is metal 1, rhodium is metal 2, platinum is metal 3
Lesson 23
- B
- A
- D
- C
- P
- C
- P
- C
- P
- C
- B
- C
- A
- D
- B
- A
- C
- A
- Chocolate chip cookie, anything with different sized parts or pieces
- Salt water, anything that has 2 or more parts evenly distributed and can be separated by physical means
- Magnetism (magnetism through distillation in any order, with the non-numbered as extra credit)
- Centrifuge
- Filtration
Evaporation
Distillation - B
- Solid to liquid
- Liquid to solid
- Gas to liquid
- Solid to gas
- Melting and freezing point
- Mass is not created nor destroyed in a reaction (or similar answer)
- 0.4 g/cm³
- 128 g
- Less than 1 g/cm³ (extra credit)
- Greater than 1 g/cm³ (extra credit)1 g/cm³ (extra credit)
Lesson 35
Fill in the Blanks:
- 2
- negative
- repel
- spins
- clockwise
- opposite
- attract
- 2
- 2
- 6
- 10
- 14
- p
- s
- 3
- 5
- 2
- opposite
- orbital
Orbital Diagram
- N (7)
- Na (11)
- C (6)
- F (9)
- Ne (10)
- O (8)
- P (15)
- Li (3)
- Mg (12)
- He (2)
- H (1)
- Al (13)
- Be (4)
- B (5)
Lesson 38
- B
- A
- C
- A
- C
- C
- A
- C
- B
- C
- B
- D
- A
- B
- A
- Three of the following:
- All matter is composed of indivisible particles called atoms
- All atoms of an element are identical, atoms of different elements have
different properties - Chemical reactions involve the combination of atoms, not the destruction
of atoms - When elements react to form compounds, they react in defined, whole number ratios.
- 3, 3, 4, 3
- 26, 26. 30, 26
- 6, 6, 8, 6
- 8, 8, 9, 8
- 7.5 x 10⁷m
- B
- A
- a. 1s² b. 1s²2s²2p³ c. 1s²2s²2p⁶3s²3p⁶4s²
- a. (↑↓)
b. (↑↓) (↑↓) (↑) (↑) (↑)
c. (↑↓) (↑↓) (↑↓) (↑↓) (↑↓) (↑↓) (↑↓) (↑↓)(↑↓) (↑↓)Extra credit:
a. may behave as a wave
b. may behave as a stream of particles (called photons or quanta)
Lesson 42
A family: A column on the periodic table
A period: A row on the periodic table
A metalloid: An element that shares characteristics of both metals and non-metals
Family that contains Bromine: Halogens
Family that contains Argon: Noble gases
Family that contains Beryllium: Alkaline earth metals
A family that contains Uranium: Actinides
Te: 6 valence electrons
P: 5 valence electrons
Bi: 5 valence electrons
Sn: 4 valence electrons
S: 6 valence electrons
Al: 3 valence electrons
Ne: 8 valence electrons
Cs: 1 valence electrons
Br: 7 valence electrons
Mg: 2 valence electrons
Lesson 49
- A
- B
- C
- D
- A
- B
- C
- A
- B
- C
- ↑
- ↓
- ↓
- ↑
- ↑
- ↑
- ↑
- ↑
- C
- B
- D
- B
- C
- A
- A
- +1
- -3
- +3
- -1
- -2
Extra credit: The atomic radius decreases across because since the number of electrons increases, the stronger the attraction between protons and electrons, pulling the electrons closer to the nucleus, causing a smaller radius. It decreases down the table because there is an increase in energy levels, with electrons farther away from the nucleus.
Lesson 53
Match the Items:
Lesson 56
Na and F, 4.0 – 0.9 = 3.1 Iconic
N and O, 3.5 – 3.0 = 0.5 Polar covalent
I and I, 2.5 -2.5 = Polar covalent
Fe and Ci, 3.0 – 1.8 = 1.2 Polar covalent
Br and I, 2.8 – 2.5 = 0.3 nonpolar covalent
Ca and O, 3.5 – 1.0 = 2.5 Iconic
Lewis Structures (link to pictures of those answers)
Lesson 61
Lesson 63
Quiz: Molecular Compounds
- prefixes
- carbon
- hydrocarbons
- alkanes
- nonmetals
- saturated
silicon dioxide SiO2
carbon tetrachloride CCl4
methane CH4
octane C8H18
dinitrogen trisulfide N2S3
butene C4H8
tetraphosphorus triselenide P4Se3
Lesson 63 (second assignment)
Multiple Choice:
- between nonmetals
- molecules
- prefixes
Matching:
- # 1 = g
- # 2 = a
- # 3 = d
- # 4 = j
- # 5 = i
- # 6 = f
- # 7 = h
- # 8 = b
- # 9 = e
- # 10 = c
Fill in the Blanks:
- carbon
- bond
- saturated
- unsaturated
- triple
- hydrocarbons
- alkane
- prefix
- -ane
- saturated
- ankenes
- double
- carbon atoms
- -ene
Lesson 68
- Ionic sodium carbonate
- Covalent diphosphorus pentoxide
- Covalent ammonia
- Ionic iron (II) sulfate
- Covalent silicon dioxide
- Ionic gallium chloride
- Ionic cobalt (II) bromide
- Covalent diboron tetrahydride
- Covalent carbon monoxide
- Covalent phosphorus
- Covalent N2O3
- Covalent N2
- Covalent CH4
- Ionic LiC2H3O2
- Covalent PF3
- Ionic V2O5
- Ionic Al(OH)3
- Ionic ZnS
- Covalent SiF4
- Ionic Ag3PO4
Lesson 81-83 (student submitted answers)
[Part 1 – Evidence]
- The unknown substance was discovered to be the anti-venom. The anti-venom
has a similar structure to that of Nelson’s allergy drug. - 167.16 g/mol.
- 598.66 g/mol.
- Adding the weight of the anti-toxin and the compound C to the weight of the peanut
allergy drug, it equals the weight of the unknown substance found in Nelson’s
bloodstream. - The unknown substance in addition to Nelson’s peanut allergy drug cancelled out
the effects of the peanut allergy drug. - Yes, Nelson did take his medication that day. However, the amount was lower than
required. - Yes. It showed how the compound C combines with the spider toxin.
- It is possible Joanna took the pills for Sam.
- They did not provide any important information.
- Yes, the peanuts and related products provided a way to cross reference with the
other evidence.
[Part 2 – Conclusions]
- Sam Mellon
- Sam was jealous of Nelson receiving all of the credit.
- Sam knew what would happen if Nelson had the anti-toxin in his bloodstream in
addition to the peanut allergy medication.
Lesson 93
Video Lab Answers:
- Mass of test tube with baking soda: 19.46 g
- Mass of empty test tube: 19.21 g
- Mass of baking soda: 0.25 g
- Mass of test tube and sodium chloride: 19.39 g
- Mass of sodium chloride: 0.18 g
- ? mol NaHCO3 = 0.25 g NaHCO3
(1 mol NaHCO3 / 84.0 g NaHCO3) = 0.0030 mol NaHCO3
(Note – 84.0 g is the Molar Mass of NaHCO3) - ? mol NaCl = 0.18 g NaCl (1 mol NaCl / 58.5 g NaCl) = 0.0031 mol NaCl
- 0.0030:0.0031 or 1:1
- NaHCO3 + HCl → NaCl + H2O + CO2 (no coefficients needed)
- 1:1
- “Although they should be the same, the experimental mole ration may be slightly different than the theoretical mole ration due to experimental error such as not allowing the test tube to be completely cooled when massing at the end or allowing some of the liquid to splatter out of the test tube when heating.” source
Lesson 119
- b. The wick of the candle is curled at the top.
- d. M is greater than or equal to one but less than ten.
- a. water displacement
- b. 1000 mm = 1 m
- c. Use multiple conversion factors.
- c. balance
- c. The chair will burn.
- b. CO
- c. pizza
- c. compound
- b. D = m / v
- True
- b. the protons and neutrons
- d. all of these
- c. 1s22s22p2
- b. indivisible
- b. mass
- c. gas
- b. 2
- c. Sc