Given a polynomial and one of its factors, find the remaining factors of the polynomial. Some of the factors may not be binomials.
One: 4x3 – 32x2 – 81x + 648; x – 8
Two: 64x3 – 528x2 – 1815x – 1331; x – 11
Solve the given equation. State the number and type of roots.
Three: x2 + 0x – 16 = 0
State the possible number of imaginary zeros in the given function.
Four: f(x) = -11x4 + 8x3 + 12x2 – 1x – 18
Five: f(x) = -13x3 + 1x2 + 11x8
Six: Find all of the zeros of the function f(x) = x3 – 17x2 + 81x – 65.
Answers ( ONE: (2x + 9)(2x – 9) TWO: (8x + 11)(8x + 11) THREE: two real roots, 4 and -4 FOUR: 4 FIVE: 2 SIX: 1, (8 + i), (8 – i) )
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